Hacktivitycon 2021
Hexahedron
Solved by: Taz34
- We are give values of n,e and c.
-
Decode them into simple numeric form using python.
- it looks like RSA, we used RsaCtfTool to decipher it.
: https://github.com/Ganapati/RsaCtfTool
python3 RsaCtfTool.py -n 112339816301925396926211289689793745814213925314273886071305785874178028552510482239036537066616690493241410015435402110525284201411608164205573122430898583517515498250410244592963132324072861567753086739636553410154316180827724708002409356129254383468446158145079982391991062389788544378839486986385137994309 -e 3 --uncipher 2217344750798178599616518881851238192046537371134831984828894413752520937378161486880269974456574131502921272953104454680926482208357166098075344508240480152890914678813031666242202555794691235412837030045499161787224264164243336308650477343133919653356349913604131486721125
here we have the flag.